3.1.94 \(\int (a+a \cos (c+d x))^{5/2} (A+C \cos ^2(c+d x)) \, dx\) [94]

3.1.94.1 Optimal result
3.1.94.2 Mathematica [A] (verified)
3.1.94.3 Rubi [A] (verified)
3.1.94.4 Maple [A] (verified)
3.1.94.5 Fricas [A] (verification not implemented)
3.1.94.6 Sympy [F(-1)]
3.1.94.7 Maxima [A] (verification not implemented)
3.1.94.8 Giac [A] (verification not implemented)
3.1.94.9 Mupad [F(-1)]

3.1.94.1 Optimal result

Integrand size = 27, antiderivative size = 169 \[ \int (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {64 a^3 (21 A+13 C) \sin (c+d x)}{315 d \sqrt {a+a \cos (c+d x)}}+\frac {16 a^2 (21 A+13 C) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{315 d}+\frac {2 a (21 A+13 C) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{105 d}-\frac {4 C (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{63 d}+\frac {2 C (a+a \cos (c+d x))^{7/2} \sin (c+d x)}{9 a d} \]

output
2/105*a*(21*A+13*C)*(a+a*cos(d*x+c))^(3/2)*sin(d*x+c)/d-4/63*C*(a+a*cos(d* 
x+c))^(5/2)*sin(d*x+c)/d+2/9*C*(a+a*cos(d*x+c))^(7/2)*sin(d*x+c)/a/d+64/31 
5*a^3*(21*A+13*C)*sin(d*x+c)/d/(a+a*cos(d*x+c))^(1/2)+16/315*a^2*(21*A+13* 
C)*sin(d*x+c)*(a+a*cos(d*x+c))^(1/2)/d
 
3.1.94.2 Mathematica [A] (verified)

Time = 0.33 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.56 \[ \int (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {a^2 \sqrt {a (1+\cos (c+d x))} (7476 A+5653 C+4 (588 A+779 C) \cos (c+d x)+4 (63 A+254 C) \cos (2 (c+d x))+260 C \cos (3 (c+d x))+35 C \cos (4 (c+d x))) \tan \left (\frac {1}{2} (c+d x)\right )}{1260 d} \]

input
Integrate[(a + a*Cos[c + d*x])^(5/2)*(A + C*Cos[c + d*x]^2),x]
 
output
(a^2*Sqrt[a*(1 + Cos[c + d*x])]*(7476*A + 5653*C + 4*(588*A + 779*C)*Cos[c 
 + d*x] + 4*(63*A + 254*C)*Cos[2*(c + d*x)] + 260*C*Cos[3*(c + d*x)] + 35* 
C*Cos[4*(c + d*x)])*Tan[(c + d*x)/2])/(1260*d)
 
3.1.94.3 Rubi [A] (verified)

Time = 0.71 (sec) , antiderivative size = 174, normalized size of antiderivative = 1.03, number of steps used = 11, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.407, Rules used = {3042, 3503, 27, 3042, 3230, 3042, 3126, 3042, 3126, 3042, 3125}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (a \cos (c+d x)+a)^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \left (a \sin \left (c+d x+\frac {\pi }{2}\right )+a\right )^{5/2} \left (A+C \sin \left (c+d x+\frac {\pi }{2}\right )^2\right )dx\)

\(\Big \downarrow \) 3503

\(\displaystyle \frac {2 \int \frac {1}{2} (\cos (c+d x) a+a)^{5/2} (a (9 A+7 C)-2 a C \cos (c+d x))dx}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int (\cos (c+d x) a+a)^{5/2} (a (9 A+7 C)-2 a C \cos (c+d x))dx}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{5/2} \left (a (9 A+7 C)-2 a C \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

\(\Big \downarrow \) 3230

\(\displaystyle \frac {\frac {3}{7} a (21 A+13 C) \int (\cos (c+d x) a+a)^{5/2}dx-\frac {4 a C \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {3}{7} a (21 A+13 C) \int \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{5/2}dx-\frac {4 a C \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

\(\Big \downarrow \) 3126

\(\displaystyle \frac {\frac {3}{7} a (21 A+13 C) \left (\frac {8}{5} a \int (\cos (c+d x) a+a)^{3/2}dx+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )-\frac {4 a C \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {3}{7} a (21 A+13 C) \left (\frac {8}{5} a \int \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{3/2}dx+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )-\frac {4 a C \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

\(\Big \downarrow \) 3126

\(\displaystyle \frac {\frac {3}{7} a (21 A+13 C) \left (\frac {8}{5} a \left (\frac {4}{3} a \int \sqrt {\cos (c+d x) a+a}dx+\frac {2 a \sin (c+d x) \sqrt {a \cos (c+d x)+a}}{3 d}\right )+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )-\frac {4 a C \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {3}{7} a (21 A+13 C) \left (\frac {8}{5} a \left (\frac {4}{3} a \int \sqrt {\sin \left (c+d x+\frac {\pi }{2}\right ) a+a}dx+\frac {2 a \sin (c+d x) \sqrt {a \cos (c+d x)+a}}{3 d}\right )+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )-\frac {4 a C \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

\(\Big \downarrow \) 3125

\(\displaystyle \frac {\frac {3}{7} a (21 A+13 C) \left (\frac {8}{5} a \left (\frac {8 a^2 \sin (c+d x)}{3 d \sqrt {a \cos (c+d x)+a}}+\frac {2 a \sin (c+d x) \sqrt {a \cos (c+d x)+a}}{3 d}\right )+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )-\frac {4 a C \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 a d}\)

input
Int[(a + a*Cos[c + d*x])^(5/2)*(A + C*Cos[c + d*x]^2),x]
 
output
(2*C*(a + a*Cos[c + d*x])^(7/2)*Sin[c + d*x])/(9*a*d) + ((-4*a*C*(a + a*Co 
s[c + d*x])^(5/2)*Sin[c + d*x])/(7*d) + (3*a*(21*A + 13*C)*((2*a*(a + a*Co 
s[c + d*x])^(3/2)*Sin[c + d*x])/(5*d) + (8*a*((8*a^2*Sin[c + d*x])/(3*d*Sq 
rt[a + a*Cos[c + d*x]]) + (2*a*Sqrt[a + a*Cos[c + d*x]]*Sin[c + d*x])/(3*d 
)))/5))/7)/(9*a)
 

3.1.94.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3125
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[-2*b*(Cos 
[c + d*x]/(d*Sqrt[a + b*Sin[c + d*x]])), x] /; FreeQ[{a, b, c, d}, x] && Eq 
Q[a^2 - b^2, 0]
 

rule 3126
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*Cos 
[c + d*x]*((a + b*Sin[c + d*x])^(n - 1)/(d*n)), x] + Simp[a*((2*n - 1)/n) 
 Int[(a + b*Sin[c + d*x])^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && EqQ[ 
a^2 - b^2, 0] && IGtQ[n - 1/2, 0]
 

rule 3230
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
(f_.)*(x_)]), x_Symbol] :> Simp[(-d)*Cos[e + f*x]*((a + b*Sin[e + f*x])^m/( 
f*(m + 1))), x] + Simp[(a*d*m + b*c*(m + 1))/(b*(m + 1))   Int[(a + b*Sin[e 
 + f*x])^m, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && NeQ[b*c - a*d, 0] 
&& EqQ[a^2 - b^2, 0] &&  !LtQ[m, -2^(-1)]
 

rule 3503
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (C_.)*sin[(e_.) + 
 (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Cos[e + f*x]*((a + b*Sin[e + f*x])^ 
(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m + 2))   Int[(a + b*Sin[e + f*x])^ 
m*Simp[A*b*(m + 2) + b*C*(m + 1) - a*C*Sin[e + f*x], x], x], x] /; FreeQ[{a 
, b, e, f, A, C, m}, x] &&  !LtQ[m, -1]
 
3.1.94.4 Maple [A] (verified)

Time = 6.31 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.70

method result size
default \(\frac {8 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (140 C \left (\sin ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-540 C \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (63 A +819 C \right ) \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-210 A -630 C \right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+315 A +315 C \right ) \sqrt {2}}{315 \sqrt {a \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, d}\) \(118\)
parts \(\frac {8 A \,a^{3} \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (3 \left (\cos ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+4 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+8\right ) \sqrt {2}}{15 \sqrt {a \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, d}+\frac {8 C \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (140 \left (\cos ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-20 \left (\cos ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+39 \left (\cos ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+52 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+104\right ) \sqrt {2}}{315 \sqrt {a \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, d}\) \(174\)

input
int((a+cos(d*x+c)*a)^(5/2)*(A+C*cos(d*x+c)^2),x,method=_RETURNVERBOSE)
 
output
8/315*cos(1/2*d*x+1/2*c)*a^3*sin(1/2*d*x+1/2*c)*(140*C*sin(1/2*d*x+1/2*c)^ 
8-540*C*sin(1/2*d*x+1/2*c)^6+(63*A+819*C)*sin(1/2*d*x+1/2*c)^4+(-210*A-630 
*C)*sin(1/2*d*x+1/2*c)^2+315*A+315*C)*2^(1/2)/(a*cos(1/2*d*x+1/2*c)^2)^(1/ 
2)/d
 
3.1.94.5 Fricas [A] (verification not implemented)

Time = 0.30 (sec) , antiderivative size = 110, normalized size of antiderivative = 0.65 \[ \int (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {2 \, {\left (35 \, C a^{2} \cos \left (d x + c\right )^{4} + 130 \, C a^{2} \cos \left (d x + c\right )^{3} + 3 \, {\left (21 \, A + 73 \, C\right )} a^{2} \cos \left (d x + c\right )^{2} + 2 \, {\left (147 \, A + 146 \, C\right )} a^{2} \cos \left (d x + c\right ) + {\left (903 \, A + 584 \, C\right )} a^{2}\right )} \sqrt {a \cos \left (d x + c\right ) + a} \sin \left (d x + c\right )}{315 \, {\left (d \cos \left (d x + c\right ) + d\right )}} \]

input
integrate((a+a*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x, algorithm="fricas")
 
output
2/315*(35*C*a^2*cos(d*x + c)^4 + 130*C*a^2*cos(d*x + c)^3 + 3*(21*A + 73*C 
)*a^2*cos(d*x + c)^2 + 2*(147*A + 146*C)*a^2*cos(d*x + c) + (903*A + 584*C 
)*a^2)*sqrt(a*cos(d*x + c) + a)*sin(d*x + c)/(d*cos(d*x + c) + d)
 
3.1.94.6 Sympy [F(-1)]

Timed out. \[ \int (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\text {Timed out} \]

input
integrate((a+a*cos(d*x+c))**(5/2)*(A+C*cos(d*x+c)**2),x)
 
output
Timed out
 
3.1.94.7 Maxima [A] (verification not implemented)

Time = 0.46 (sec) , antiderivative size = 155, normalized size of antiderivative = 0.92 \[ \int (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {84 \, {\left (3 \, \sqrt {2} a^{2} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 25 \, \sqrt {2} a^{2} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 150 \, \sqrt {2} a^{2} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} A \sqrt {a} + {\left (35 \, \sqrt {2} a^{2} \sin \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 225 \, \sqrt {2} a^{2} \sin \left (\frac {7}{2} \, d x + \frac {7}{2} \, c\right ) + 756 \, \sqrt {2} a^{2} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 2100 \, \sqrt {2} a^{2} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 8190 \, \sqrt {2} a^{2} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} C \sqrt {a}}{2520 \, d} \]

input
integrate((a+a*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x, algorithm="maxima")
 
output
1/2520*(84*(3*sqrt(2)*a^2*sin(5/2*d*x + 5/2*c) + 25*sqrt(2)*a^2*sin(3/2*d* 
x + 3/2*c) + 150*sqrt(2)*a^2*sin(1/2*d*x + 1/2*c))*A*sqrt(a) + (35*sqrt(2) 
*a^2*sin(9/2*d*x + 9/2*c) + 225*sqrt(2)*a^2*sin(7/2*d*x + 7/2*c) + 756*sqr 
t(2)*a^2*sin(5/2*d*x + 5/2*c) + 2100*sqrt(2)*a^2*sin(3/2*d*x + 3/2*c) + 81 
90*sqrt(2)*a^2*sin(1/2*d*x + 1/2*c))*C*sqrt(a))/d
 
3.1.94.8 Giac [A] (verification not implemented)

Time = 0.93 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.13 \[ \int (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {\sqrt {2} {\left (35 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 225 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (\frac {7}{2} \, d x + \frac {7}{2} \, c\right ) + 252 \, {\left (A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 3 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 2100 \, {\left (A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 630 \, {\left (20 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 13 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} \sqrt {a}}{2520 \, d} \]

input
integrate((a+a*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x, algorithm="giac")
 
output
1/2520*sqrt(2)*(35*C*a^2*sgn(cos(1/2*d*x + 1/2*c))*sin(9/2*d*x + 9/2*c) + 
225*C*a^2*sgn(cos(1/2*d*x + 1/2*c))*sin(7/2*d*x + 7/2*c) + 252*(A*a^2*sgn( 
cos(1/2*d*x + 1/2*c)) + 3*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(5/2*d*x + 5 
/2*c) + 2100*(A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + C*a^2*sgn(cos(1/2*d*x + 1/ 
2*c)))*sin(3/2*d*x + 3/2*c) + 630*(20*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 13 
*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(1/2*d*x + 1/2*c))*sqrt(a)/d
 
3.1.94.9 Mupad [F(-1)]

Timed out. \[ \int (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\int \left (C\,{\cos \left (c+d\,x\right )}^2+A\right )\,{\left (a+a\,\cos \left (c+d\,x\right )\right )}^{5/2} \,d x \]

input
int((A + C*cos(c + d*x)^2)*(a + a*cos(c + d*x))^(5/2),x)
 
output
int((A + C*cos(c + d*x)^2)*(a + a*cos(c + d*x))^(5/2), x)